Refractive index of optical coating

According to the basic theory of electromagnetism, transmission and reflection for different media are mentioned.

If it is vertically incident from medium N1 to N2

Reflectivity = [(n2-n1) / (N1 + N2)] ^ 2

Penetration rate = 4n1n2 / (N1 + N2) ^ 2

Example explanation:

If the refractive index of air is 1.0, the refractive index of coating NC (e.g. 1.5), and the refractive index n (e.g. 1.8) (1) of glass enter the glass directly from air

Penetration rate = 4 × one × 1.8 / ( 1+1.8 )2=91.84%

(2) Penetration rate of air entering the coating and then entering the glass = [4 × one × 1.5 / ( 1+1.5 )2] × [ 4 × one point five × 1.8 / ( 1.5+1.8 )2]=95.2%

It can be seen that coated glass will increase light transmittance. In addition, according to this formula, we can calculate the light penetration on both sides of the lens. It is found that even a perfect lens (refractive index 1.8) has a transmittance of about 85%. If a coating is added (refractive index 1.5), the transmittance can reach 91%. The importance of visible optical coating.

Refractive index of optical coating


Hanzhong Brisun Optics Co., Ltd. Is the high precision optical element manufacturer provides customized production of Various optical lenses, including spherical lens, cylindrical lens, optical window, mirror, prism, filter, metal base mirror and other high-precision optical elements. The base materials include various optical glass, fused quartz, calcium fluoride (CaF2), zinc selenide (ZnSe), germanium (GE), silicon (SI), sapphire, metal and other materials. And provide antireflective film, high reflection film, spectroscopic film, metal film and other optical coatings.

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